All my math notes, now in Markdown.

You should be able to

- Identify Conics
- Graph Conics from polar form
- Write polar to / from rectangular

Any conic section can be defined as the locus of points whose distances to a point (the focus) and a line (the directrix) have a *constant ratio*. That ratio is the eccentricity, denoted as $e$.

if $0 < e < 1$, the conic is an ellipse

if $e = 1$, the conic is a parabola

if $e > 1$, the conic is a hyperbola

For any point $P(x, y)$ on the curve $D(x, y)$ on the directrix and $F(x, y)$ the focus at pole, the ratio of $PF/PD$ equals the eccentricity. $k$ is the distance between the focus and directrix.

\[e = \frac{PF}{PD} \Rightarrow PF = e * PD\]The graph of a conic in polar form, with *focus at pole*, is given by
\(r = \frac{ek}{1 \pm e \cos{\theta}}\ or\ r = \frac{ek}{1 \pm e \sin{\theta}}\)
where $e$ = eccentricity, and $k$ is the distance between the focus and directrix.

The directrix is perpendicular to the major axis, the axis of symmetry, and the transverse axis.

$\cos{\theta}$ has polar axis symmetry and $\sin{\theta}$ has $\theta = \frac{\pi}{2}$ symmetry.

$r = \frac{ek}{1 + e\cos{\theta}}$ vertical directrix right of the pole

$r = \frac{ek}{1 - e\cos{\theta}}$ vertical directrix left of the pole

$r = \frac{ek}{1 + e\sin{\theta}}$ horizontal directrix above the pole

$r = \frac{ek}{1 - e\sin{\theta}}$ horizontal directrix below the pole

Given $r=\frac{16}{5-3\cos\theta}$, identify the conic, graph (including directrix), and write it in rectangular standard form.

- Find a polar equation for the conic with focus at the pole and eccentricity $e=7/3$ and directrix $y=-1$
- Determine the type of conic and graph. $r=\frac{24}{4+2\sin\theta}$
- Determine the type of conic and graph. $r=\frac{16}{3+5\cos\theta}$
- Determine the type of conic and graph. $r=\frac{2}{1-\cos\theta}$
- Determine the Cartesian equation (rectangular form) for the given conic. $r=\frac{4}{2-\sin\theta}$
- Determine the Cartesian equation (rectangular form) for the given conic. $r=\frac{6}{1+2\cos\theta}$
- Determine the Cartesian equation (rectangular form) for the given conic. $r=\frac{2}{1-\cos\theta}$
- Determine the Cartesian equation (rectangular form) for the given conic. $r=\frac{4}{2-2\cos\theta}$
- Write an equation for an ellipse in polar form with focus at pole and given the polar coordinates $(1.5,0),(6,\pi)$ that are on the major axis.
- Write an equation for a hyperbola in polar form with focus at pole and given the polar coordinates $(-6,\frac \pi 2),(2,\frac{3\pi}{2})$ as endpoints of its transverse axis.
- Write the following in polar form. $\frac{(x-4)^2}{25}+\frac{y^2}{9}=1$